Hash of Int64 and || operator?

Help & Support
1

hello,

i want to remove duplicates from my hdd so i wrote this code

which is a companion for `find ~ -type f -printf “%s %p\n”.

i tried to store the sizes as Int64 instead but now have this message

20 | (seen[size] ||= [] of String ).push(filename)
^-
Error: no overload matches ‘Hash(Int64, Array(String))#[]=’ with types Int32, Array(String)

as i’m very new to crystal, try to work around it. any help (or other feedback about the repo itself) is welcome

2

I’m guessing you tried to convert it to Int64 like this:

size,filename = l.split(" ",2)
size = size.to_i
( seen[size] ||= [] of String ).push(filename)

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The error you mentioned is because #to_i convert to Int32. The solution is to use #to_i64:

size,filename = l.split(" ",2)
size = size.to_i64
( seen[size] ||= [] of String ).push(filename)

Play Link

However, I had some trouble figuring out what your question was, so please let me know (and clarify) if it doesn’t help.

3

@eiro Could you submit the failing code? Otherwise we don’t know what you tried (the code you posted works just fine).

1 Like
4

hello,

I’m guessing you tried to convert it to Int64 like this:

size,filename = l.split(" ",2)
size = size.to_i
( seen[size] ||= [] of String ).push(filename)

this is exactly what i did!

The error you mentioned is because #to_i convert to Int32. The solution is to use #to_i64

well … the message was somewhat explicit but i assumed that crystal
can infer the expected type because of the declaration of seen.

thanks a lot.

However, I had some trouble figuring out what your question was, so
please let me know (and clarify) if it doesn’t help.

i’m really sorry if i was confusing. your anwser fit the need perfectly.

regards,
marc

5

Hello Ary,

@eiro Could you submit the failing code? Otherwise we don’t know what
you tried (the code you posted works just fine).

next time, i’ll push a “failing” branch. promise :)

regards
marc